>Psychtoolbox>PsychOneliners

outputcell = Explode(vect,splitvect,mode)
[out1,out2,…] = Explode(vect,splitvect,mode)

Split a string or vector VECT by a string, scalar or vector SPLITSVECT.
Output OUTPUTCELL will be returned as an array of cells.

Both VECT and SPLITSVECT must be a string or numeric vector of length 1
or more.

The way this function handles its input is different for strings and
numeric datatypes.

strings
SPLITSVECT can be specified using two formats (MODE):
If MODE is not specified, ‘fixed’ will be used

‘fixed’ : a fixed string, which will be used literally to split
VECT. Some character combinations have a special meaning:
\b Backspace
\f Form feed
\n New line
\r Carriage return
\t Horizontal tab
example:
s1 = ‘resp32|me too|”get over here”’;
s2 = Explode(s1,’|’); or s2 = Explode(s1,’|’,’fixed’);
s2(:)
ans =
‘resp32’
‘me too’
‘“get over here”’

‘variable’ : if you want to split the input with on a string that
matches a certain pattern.
specify this pattern using a regular expression,
see “doc regexp”
example:
s1 = ‘|fff|ja|fdf|er|fft|fofr|’;
s2 = Explode(s1,’f.f’,’variable’); % . means any character
s2(:)
ans =
‘|’
‘|ja|’
‘|er|fft|’
‘r|’

numerical vectors
SPLITSVECT can be specified using two formats (MODE):
If MODE is not specified, ‘fixed’ will be used
NB: splitting floats works, but precision will be lost

‘fixed’ : a fixed number or sequence of numbers, which will be used
literally to split the vector.
example:
n1 = [inf 33 12 45 13 nan 46 74 12 45 15 64];
n2 = Explode(n1,[12 45]); of n2 = Explode(s1,[12 45],’fixed’);
n2(:)
ans =
[Inf 33]
[ 13 NaN 46 74]
[ 15 64]
n2 = Explode(n1,12);
n2(:)
ans =
[Inf 33]
[ 45 13 NaN 46 74]
[ 45 15 64]

‘variable’ : If you want to split on a sequence of numbers that
contains (a) wildcard(s). Each wilcard can match a single
item in the vector.
NaN specifies a wildcard. When using ‘variable’ for
numeric input, you can thus no longer use NaN in your
pattern.
example:
n1 = [inf 33 12 45 13 nan 46 74 12 35 64 13 21];
n2 = Explode(n1,[12 nan 13],’variable’);
n2(:)
ans =
[Inf 33]
[NaN 46 74 12 35 64 13 21]

              n2 = [Explode](Explode)(n1,[12 nan nan 13],'variable');  
              n2(:)  
              ans =   
                  [Inf    33    12    45    13   [NaN](NaN)    46    74]  
                  [21]